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통계학:이항분포 [2025/09/24 13:23] – [정의] masteraccount통계학:이항분포 [2025/09/24 13:24] (current) – [공식사용예문] masteraccount
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 4. 계산 : \\ 4. 계산 : \\
-$ p(2, 3, 0.5)  =  \binom{3}{2} p^(1-0.5)^{3-2} $ 가된다.\\+$ p(2, 3, 0.5)  =  \binom{3}{2} p^(1-0.5)^{3-2} $ 가된다.\\
 \\ \\
 $\binom{3}{2} = \frac{3!}{2!(3-2)!} = 3$ \\ $\binom{3}{2} = \frac{3!}{2!(3-2)!} = 3$ \\
  • 통계학/이항분포.1758720225.txt.gz
  • Last modified: 2025/09/24 13:23
  • by masteraccount